1) Let’s describe this rotation that maps \(ABCD\) on to \(A’B’C’D’\). To properly describe the transformation, we need three parts:
PART 1: Which point is the center of the rotation? PART 2: What is the angle of the rotation? PART 3: What is the direction of the rotation (clockwise or counter-clockwise)? Answer all three parts as it relates to the diagram. |
3) Let’s do a \(90^{\circ}\) counter-clockwise rotation of point \(A\) about the origin.
a) Draw \(\overrightarrow{OA}\) b) Determine slope of \(\overrightarrow{OA}\) (the rise to run ratio). Note: do not simplify the ratio. c) Use the opposite reciprocal slope (rise to run ratio) of \(\overrightarrow{OA}\) to plot \(A’\) from point \(O\). d) Draw \(\overrightarrow{OA’}\) and show that the measure of \(\angle AOA’\) is \(90^{\circ}\). |
For #4 - 8 use coordinate rules to rotate the given object the given angle counter-clockwise about the origin.
4) Point \(P (5, 4)\); \(90^{\circ}\)
5) \(\overline{MN}\) with \(M(-1, 3)\) and \(N(4, -2)\); \(180^{\circ}\)
6) \(\triangle XYZ\) with \(X(0, 0)\), \( Y(-7, 5)\), and \(Z(-3, 6)\); \( 270^{\circ}\)
4) Point \(P (5, 4)\); \(90^{\circ}\)
5) \(\overline{MN}\) with \(M(-1, 3)\) and \(N(4, -2)\); \(180^{\circ}\)
6) \(\triangle XYZ\) with \(X(0, 0)\), \( Y(-7, 5)\), and \(Z(-3, 6)\); \( 270^{\circ}\)
12) Plot \(C’S’O’\) after a \(90^{\circ}\) clockwise rotation about point \(P\). Move the points to the correct location.
13) Rotate quadrilateral \(COLD\) \( 90^{\circ}\) counter-clockwise about point \(P(1, 0)\).
\(C’\)______ \(O’\)______ \(L'\)______ \(D’\)______
\(C’\)______ \(O’\)______ \(L'\)______ \(D’\)______
14) Rotate line \(m\) about point \(P(2, 1)\) \( 270^{\circ}\) counter-clockwise
\(F’\)______ \(O’\)______ \(U’\)______ \(R’\)______
\(F’\)______ \(O’\)______ \(U’\)______ \(R’\)______
15) Construct a center of rotation and label the point \(P\). Create a rotation of four angle measures (two positive and two negative).